2x^2+4y^2-12=0

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Solution for 2x^2+4y^2-12=0 equation:


Simplifying
2x2 + 4y2 + -12 = 0

Reorder the terms:
-12 + 2x2 + 4y2 = 0

Solving
-12 + 2x2 + 4y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 2x2 + 12 + 4y2 = 0 + 12

Reorder the terms:
-12 + 12 + 2x2 + 4y2 = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 2x2 + 4y2 = 0 + 12
2x2 + 4y2 = 0 + 12

Combine like terms: 0 + 12 = 12
2x2 + 4y2 = 12

Add '-4y2' to each side of the equation.
2x2 + 4y2 + -4y2 = 12 + -4y2

Combine like terms: 4y2 + -4y2 = 0
2x2 + 0 = 12 + -4y2
2x2 = 12 + -4y2

Divide each side by '2'.
x2 = 6 + -2y2

Simplifying
x2 = 6 + -2y2

Reorder the terms:
-6 + x2 + 2y2 = 6 + -2y2 + -6 + 2y2

Reorder the terms:
-6 + x2 + 2y2 = 6 + -6 + -2y2 + 2y2

Combine like terms: 6 + -6 = 0
-6 + x2 + 2y2 = 0 + -2y2 + 2y2
-6 + x2 + 2y2 = -2y2 + 2y2

Combine like terms: -2y2 + 2y2 = 0
-6 + x2 + 2y2 = 0

The solution to this equation could not be determined.

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